t=3t^2-t+1

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Solution for t=3t^2-t+1 equation: 



t=3t^2-t+1

We move all terms to the left:

t-(3t^2-t+1)=0

We get rid of parentheses

-3t^2+t+t-1=0

We add all the numbers together, and all the variables

-3t^2+2t-1=0

a = -3; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·(-3)·(-1)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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